CS61A HW1
CS61A HW1 Page: https://inst.eecs.berkeley.edu/~cs61a/fa20/hw/hw01/
Instructions ☘️
Download hw01.zip.
Submission: When you are done, submit with python3 ok --submit
. You may submit more than once before the deadline; only the final submission will be scored. Check that you have successfully submitted your code on okpy.org. See Lab 0 for more instructions on submitting assignments.
Using Ok: If you have any questions about using Ok, please refer to this guide.
Readings: You might find the following references useful:
Note: Some of these readings necessary for the homework questions will not be covered until Monday’s lecture on Control.
Grading: Homework is graded based on correctness. Each incorrect problem will decrease the total score by one point. There is a homework recovery policy as stated in the syllabus. This homework is out of 2 points.
Required Questions 🧐
Q1: Syllabus Quiz
Please fill out our Syllabus Quiz based off of our policies found on our syllabus page.
Q2: A Plus Abs B
Fill in the blanks in the following function for adding a
to the absolute value of b
, without calling abs
. You may not modify any of the provided code other than the two blanks.
from operator import add, sub
def a_plus_abs_b(a, b):
"""Return a+abs(b), but without calling abs.
>>> a_plus_abs_b(2, 3)
5
>>> a_plus_abs_b(2, -3)
5
>>> # a check that you didn't change the return statement!
>>> import inspect, re
>>> re.findall(r'^\s*(return .*)', inspect.getsource(a_plus_abs_b), re.M)
['return f(a, b)']
"""
if b < 0:
f = _____
else:
f = _____
return f(a, b)
Use Ok to test your code:
python3 ok -q a_plus_abs_b
Q3: Two of Three
Write a function that takes three positive numbers as arguments and returns the sum of the squares of the two smallest numbers. Use only a single line for the body of the function.
def two_of_three(x, y, z):
"""Return a*a + b*b, where a and b are the two smallest members of the
positive numbers x, y, and z.
>>> two_of_three(1, 2, 3)
5
>>> two_of_three(5, 3, 1)
10
>>> two_of_three(10, 2, 8)
68
>>> two_of_three(5, 5, 5)
50
>>> # check that your code consists of nothing but an expression (this docstring)
>>> # a return statement
>>> import inspect, ast
>>> [type(x).__name__ for x in ast.parse(inspect.getsource(two_of_three)).body[0].body]
['Expr', 'Return']
"""
return _____
Hint: Consider using the
max
ormin
function:>>> max(1, 2, 3) 3 >>> min(-1, -2, -3) -3
Use Ok to test your code:
python3 ok -q two_of_three
Q4: Largest Factor
Write a function that takes an integer n
that is greater than 1 and returns the largest integer that is smaller than n
and evenly divides n
.
def largest_factor(n):
"""Return the largest factor of n that is smaller than n.
>>> largest_factor(15) # factors are 1, 3, 5
5
>>> largest_factor(80) # factors are 1, 2, 4, 5, 8, 10, 16, 20, 40
40
>>> largest_factor(13) # factor is 1 since 13 is prime
1
"""
"*** YOUR CODE HERE ***"
Hint: To check if
b
evenly dividesa
, you can use the expressiona % b == 0
, which can be read as, “the remainder of dividinga
byb
is 0.”
Use Ok to test your code:
python3 ok -q largest_factor
Q5: If Function vs Statement
Let’s try to write a function that does the same thing as an if
statement.
def if_function(condition, true_result, false_result):
"""Return true_result if condition is a true value, and
false_result otherwise.
>>> if_function(True, 2, 3)
2
>>> if_function(False, 2, 3)
3
>>> if_function(3==2, 3+2, 3-2)
1
>>> if_function(3>2, 3+2, 3-2)
5
"""
if condition:
return true_result
else:
return false_result
Despite the doctests above, this function actually does not do the same thing as an if
statement in all cases. To prove this fact, write functions cond
, true_func
, and false_func
such that with_if_statement
prints the number 47
, but with_if_function
prints both 42
and 47
.
def with_if_statement():
"""
>>> result = with_if_statement()
47
>>> print(result)
None
"""
if cond():
return true_func()
else:
return false_func()
def with_if_function():
"""
>>> result = with_if_function()
42
47
>>> print(result)
None
"""
return if_function(cond(), true_func(), false_func())
def cond():
"*** YOUR CODE HERE ***"
def true_func():
"*** YOUR CODE HERE ***"
def false_func():
"*** YOUR CODE HERE ***"
Hint: If you are having a hard time identifying how an
if
statement andif_function
differ, consider the rules of evaluation forif
statements and call expressions.
Use Ok to test your code:
python3 ok -q with_if_statement
python3 ok -q with_if_function
Q6: Hailstone
Douglas Hofstadter’s Pulitzer-prize-winning book, Gödel, Escher, Bach, poses the following mathematical puzzle.
- Pick a positive integer
n
as the start. - If
n
is even, divide it by 2. - If
n
is odd, multiply it by 3 and add 1. - Continue this process until
n
is 1.
The number n
will travel up and down but eventually end at 1 (at least for all numbers that have ever been tried – nobody has ever proved that the sequence will terminate). Analogously, a hailstone travels up and down in the atmosphere before eventually landing on earth.
Breaking News (or at least the closest thing to that in math). There was a recent development in the hailstone conjecture last year that shows that almost all numbers will eventually get to 1 if you repeat this process. This isn’t a complete proof but a major breakthrough.
This sequence of values of n
is often called a Hailstone sequence. Write a function that takes a single argument with formal parameter name n
, prints out the hailstone sequence starting at n
, and returns the number of steps in the sequence:
def hailstone(n):
"""Print the hailstone sequence starting at n and return its
length.
>>> a = hailstone(10)
10
5
16
8
4
2
1
>>> a
7
"""
"*** YOUR CODE HERE ***"
Hailstone sequences can get quite long! Try 27. What’s the longest you can find?
Use Ok to test your code:
python3 ok -q hailstone
Submit 🚀
Make sure to submit this assignment by running:
python3 ok --submitpy
Solution 🧑🏻💻
Ricky’s GitHub Repository for CS61A: https://github.com/Ricky2333/CS61A
Due to the course policies, this is a private repository only for self-review.
If you have any questions, feel free to contact me through the social links on my homepage.
Ricky’s Homepage: https://rickyxcoder.top/